2x^2+58=10

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Solution for 2x^2+58=10 equation: 



2x^2+58=10

We move all terms to the left:

2x^2+58-(10)=0

We add all the numbers together, and all the variables

2x^2+48=0

a = 2; b = 0; c = +48;
Δ = b2-4ac
Δ = 02-4·2·48
Δ = -384
Delta is less than zero, so there is no solution for the equation

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